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Question: If x<sup>2</sup> + 6x – 27 \> 0 and x<sup>2</sup> – 3x – 4 \< 0, then –...

If x2 + 6x – 27 > 0 and x2 – 3x – 4 < 0, then –

A

x > 3

B

x < 4

C

3 < x < 4

D

x = 3.5

Answer

3 < x < 4

Explanation

Solution

(x + 9) (x – 3) > 0; x2 – 3x – 4 < 0

x ∈ (–∞, –9) ∪ (3, ∞) (x – 4) (x + 1) < 0

⇒ x ∈ (–1, 4)

Hence, x ∈ (–1, 9) ∪ (3,4)