Question

If (x₁, y₁) is a point on the hyperbola $\frac{x^{2}}{64}$– $\frac{y^{2}}{36}$= 1 in the first quadrant whose distance from right focus is $\frac{9}{2}$ then (x₁ + y₁) must be-

• A. $\frac{29}{2}$
• B. $\frac{19}{2}$
• C. $\frac{31}{2}$
• D. –7

Answer 1

Answer: (A)

$\frac{29}{2}$

Answer 2

$\frac{x^{2}}{64}$–$\frac{y^{2}}{36}$= 1 … (1)

Ž a² = 64; b² = 36

Q e = $\sqrt{1 + \frac{b^{2}}{a^{2}}}$

Given PS = $\frac{9}{2}$

Ž (x₁ + y₁) = ?