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Question

Question: If x<sub>1</sub> and x<sub>2</sub> are the arithmetic and harmonic mean of the roots of the equation...

If x1 and x2 are the arithmetic and harmonic mean of the roots of the equations ax2 + bx + c = 0, then quadratic equation whose roots are x1 and x2 is

A

abx2 + (b2 + ac)x + bc = 0

B

2ab x2 + (b2 + 4ac)x + 2bc = 0

C

2abx2 + (b2 + ac)x + bc = 0

D

None of these

Answer

2ab x2 + (b2 + 4ac)x + 2bc = 0

Explanation

Solution

a + b = – ba\frac{b}{a}, ab = ca\frac{c}{a}

x2 – x (α+β2+2αβα+β)\left( \frac{\alpha + \beta}{2} + \frac{2\alpha\beta}{\alpha + \beta} \right) + ab = 0

x2 + x(b2+4ac2ab)+ca\left( \frac{b^{2} + 4ac}{2ab} \right) + \frac{c}{a}= 0

i.e. 2ab x2 + (b2 + 4ac) x + 2bc = 0