Question

If $x\sin 45{^\circ}\cos^{2}60{^\circ} = \frac{\tan^{2}60{^\circ}\text{cosec}30{^\circ}}{\sec 45{^\circ}\cot^{2}30{^\circ}}$, then $x =$

• A. 2
• B. 4
• C. 8
• D. 16

Answer 1

Answer: (C)

8

Answer 2

$x.\frac{1}{\sqrt{2}}.\frac{1}{4} = \frac{3.2}{\sqrt{2}.3} \Rightarrow \frac{x}{4\sqrt{2}} = \sqrt{2} \Rightarrow x = 8$.