Question
Question: If \(x,\mspace{6mu} y,\mspace{6mu} z\), then the roots of the equation \(u = x^{2} + 4y^{2} + 9z^{2...
If x,6muy,6muz, then the roots of the equation
u=x2+4y2+9z2−6yz−3zx−zxy are.
A
Equal
B
Imaginary
C
Real
D
None of these
Answer
Real
Explanation
Solution
We have a∈[2,8] Let roots are a∈[−2,8] and a∈(2,8)
Let a∈(−2,8)p,q∈{1,2,3,4}
Given that, px2+qx+1=0
Putting this value, we get
x2−(3k−1)x+.
Hence roots are real.