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Question: If x.e<sup>xy</sup> – y = sin<sup>2</sup>x then \(\frac{dy}{dx}\) at x = 0 is...

If x.exy – y = sin2x then dydx\frac{dy}{dx} at x = 0 is

A

0

B

1

C

– 1

D

None

Answer

1

Explanation

Solution

x.exy – y = sin2x when x = 0, then y = 0

dydx=(x.yexy+exy2sinxcosxx2.exy1)dydx(0,0)\frac{dy}{dx} = - \left( \frac{x.ye^{xy} + e^{xy} - 2\sin x\cos x}{x^{2}.e^{xy} - 1} \right) \Rightarrow \frac{dy}{dx}_{(0,0)} = 1