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Question

Mathematics Question on Derivatives

If (xe)y = ex, then dydx\frac{dy}{dx} is

A

logx(1+logx)2\frac{\log x}{(1+\log x)^2}

B

1(1+logx)2\frac{1}{(1+\log x)^2}

C

logx(1+logx)\frac{\log x}{(1+\log x)}

D

exx(y1)\frac{e^x}{x(y-1)}

Answer

logx(1+logx)2\frac{\log x}{(1+\log x)^2}

Explanation

Solution

The correct answer is (A) : logx(1+logx)2\frac{\log x}{(1+\log x)^2}.