Question
Question: If \(x^{2} + x + a = 0\) are real and \(2 < a < 3\), then the roots of the equation \(a > 3\)are....
If x2+x+a=0 are real and 2<a<3, then the roots of the equation a>3are.
A
Complex
B
Real and distinct
C
Real and equal
D
None of these
Answer
Real and distinct
Explanation
Solution
Given equation is 1−b
Its discriminant b−1α,β2x2−2(m2+1)x+m4+m2+1=0
which is positive, since α2+β2 are real and m2.
Hence roots are real and distinct.