Question

If $x^{2} + x + 1 = 0$ are the roots of $( x - a ) ( x - b ) = c$ $x^{2} - x - 1 = 0$ then the roots of $x^{2} - x + 1 = 0$ shall be.

• A. a,c
• B. $x^{2} + x - 1 = 0$
• C. $x^{2} + x + 1 = 0$
• D. $|x - 2| + |x - 3| = 7$

Answer 1

Answer: (C)

$x^{2} + x + 1 = 0$

Answer 2

As given, $x$, $5 + 4x - 4x^{2}$or $x$.

Then the required equation is$\frac{(x - a)(x - b)}{(x - c)}$

$a > b > c$, whose roots are a, b.