Question

If $x^{2} - 5 = A(x - 2) + B(x - 1) + C(x - 1)(x - 2)$ then x =

• A. $C = 1,A + B - 3C = 0, - 2A - B + 2C = - 5$
• B. $\therefore$
• C. $A = 4,B = - 1,C = 1$
• D. None of these

Answer 1

Answer: (B)

$\therefore$

Answer 2

$y = \log_{b}c,z = \log_{c}a$

$x\ln a = y\ln b = xy\ln(ab) = k(\text{say})xyz = \log_{a}b.\log_{b}c.\log_{c}a = 1$

$y = 3^{12} \times 2^{8} \Rightarrow$.