Question
Question: If x, y, z are integers in A.P., lying between 1 and 9, and x51, y41 and z31 are three digit number...
If x, y, z are integers in A.P., lying between 1 and 9, and x51,
y41 and z31 are three digit numbers then the value of
5x51x4y41y3z31z is
A
x + y + z
B
0
C
x – y + z
D
x – y – z
Answer
0
Explanation
Solution
5 & 4 & 3 \\
100x + 51 & 100y + 41 & 100y + 31 \\
x & y & z
\end{matrix} \right|$$
R<sub>1</sub> → R<sub>2</sub> – (100R<sub>3</sub>)
∆ = $\left| \begin{matrix}
5 & 4 & 3 \\
51 & 41 & 31 \\
x & y & z
\end{matrix} \right|$⇒ ∆ = 0