Question
Question: If x + y = 12 and xy = 14, find the value of \({{x}^{2}}+{{y}^{2}}\) (a). 113 (b). 64 (c). 116...
If x + y = 12 and xy = 14, find the value of x2+y2
(a). 113
(b). 64
(c). 116
(d). 183
Solution
Hint: We have been given the value of x + y and xy, so we can use the formula (x+y)2=x2+y2+2xy and then we will substitute the value of x + y and xy in the formula and then we will perform some algebraic operations to find the value of x2+y2.
Complete step-by-step answer:
Let’s start our solution.
We know the value of x + y and xy, so the only formula that comes in our mind by seeing what is given and what we need find is (x+y)2=x2+y2+2xy
Now we have to substitute all the given values in the equation and then solve it,
So, substituting the value of x + y = 12 and xy = 14 in (x+y)2=x2+y2+2xy we get,
(12)2=x2+y2+2(14)
Now taking all the constant to one side and the variable to other side we get,
x2+y2=144−28x2+y2=116
Hence, the value of x2+y2 is 116.
So, the correct answer option (c).
Note: One can also solve this question by solving x + y = 12 and xy = 14, and try to solve these two equations and find the value of x and y. Then we can put the value of x and y in x2+y2 and find its value. Both the methods are good but the method that has been used in this solution is quicker and involves less calculation.