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Question: If x & y \> 0, x \> y then tan<sup>–1</sup>![](https://cdn.pureessence.tech/canvas_516.png?top_left_...

If x & y > 0, x > y then tan–1+ tan–1 (x+yxy)\left( \frac { x + y } { x - y } \right) is equal to

A

–p/4

B

p/4

C

3p/4

D

None of these

Answer

3p/4

Explanation

Solution

since xy×x+yxy\frac { x } { y } \times \frac { x + y } { x - y } > 1

given sum = p + tan–1(xy+x+yxy1xyx+yxy)\left( \frac { \frac { x } { y } + \frac { x + y } { x - y } } { 1 - \frac { x } { y } \cdot \frac { x + y } { x - y } } \right)

= p + tan–1(–1) = 3p/4