If (x = \sqrt{a^{sin^{-1} t}}), (y = \sqrt{a^{ cos^{-1}t}})... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

If $x = \sqrt{a^{sin^{-1} t}}$ , $y = \sqrt{a^{ cos^{-1}t}}$ then $\frac{dy}{dx}$ is:

A

$\frac{y}{x}$

B

$-\frac{y}{x}$

C

$-\frac{y^2}{x}$

D

$-\frac{y}{x^2}$

Answer

$-\frac{y}{x}$

Explanation

Solution

The correct option is (B): $-\frac{y}{x}$