Question
Mathematics Question on Trigonometric Functions
If x=sin1,y=sin2,z=sin3 then
A
x < y < z
B
x > y > z
C
y < z < x
D
z < x < y
Answer
z < x < y
Explanation
Solution
Clearly sin1<sin2 but sin3<sin1[∵sin is decreasing in (π/2,3π/2)]
If x=sin1,y=sin2,z=sin3 then
x < y < z
x > y > z
y < z < x
z < x < y
z < x < y
Clearly sin1<sin2 but sin3<sin1[∵sin is decreasing in (π/2,3π/2)]