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Question

Mathematics Question on Trigonometric Functions

If x=sin1,y=sin2,z=sin3x = \sin 1, y = \sin 2 , z = \sin 3 then

A

x < y < z

B

x > y > z

C

y < z < x

D

z < x < y

Answer

z < x < y

Explanation

Solution

Clearly sin1<sin2\sin 1 < \sin 2 but sin3<sin1[sin\sin 3 < \sin 1\, \, \, \, \, \, \, \, \, [\because \, \, \, \, \sin is decreasing in (π/2,3π/2)]( \pi / 2 , 3 \pi / 2)]