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Question

Question: If \(x = \log(y + \sqrt{y^{2} + 1}),\) then \(y =\)...

If x=log(y+y2+1),x = \log(y + \sqrt{y^{2} + 1}), then y=y =

A

tanhx\tanh x

B

cothx\coth x

C

sinhx\sinh x

D

coshx{\cos h}x

Answer

sinhx\sinh x

Explanation

Solution

x=sinh1x = \sinh^{- 1}{}y=sinhxy = {\sin h}x