Question

If x is real then minimum value of x² – 8x + 17 is

• A. –1
• B. 0
• C. 1
• D. 2

Answer 1

Answer: (C)

1

Answer 2

Min. Value = –$\frac{D}{4A}$ = –$\frac{(64 - 68)}{4}$ = 1