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Question

Question: If x is real number such that \(\left| \begin{matrix} x + 1 & x + 2 & x + \alpha \\ x + 2 & x + 3 & ...

If x is real number such that x+1x+2x+αx+2x+3x+βx+3x+4x+γ\left| \begin{matrix} x + 1 & x + 2 & x + \alpha \\ x + 2 & x + 3 & x + \beta \\ x + 3 & x + 4 & x + \gamma \end{matrix} \right| = 0 .

Then a, b, g are in

A

A.P

B

G.P

C

H.P.

D

None of these

Answer

A.P

Explanation

Solution

(i) R3 ® R3 – R2

(ii) R2 ® R2 – R1

x+1x+2x+α11βα11γβ\left| \begin{matrix} x + 1 & x + 2 & x + \alpha \\ 1 & 1 & \beta - \alpha \\ 1 & 1 & \gamma - \beta \end{matrix} \right|

x+1x+2x+α002βαγ11γβ\left| \begin{matrix} x + 1 & x + 2 & x + \alpha \\ 0 & 0 & 2\beta - \alpha - \gamma \\ 1 & 1 & \gamma - \beta \end{matrix} \right| = 0;R2 ® R2 – R3

expanding by 2nd row –(2b – a – g) (–1) = 0

2b = a + g

a, b, g are in AP.