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Question: If x is real number in [0, 1], then the value of \(\frac{x}{2}\) [1 + cos<sup>2m</sup> (n!πx)] is g...

If x is real number in [0, 1], then the value of

x2\frac{x}{2} [1 + cos2m (n!πx)] is given by

A

2 or 1 according as x is rational or irrational

B

1 or 2 according as x is rational or irrational

C

1 for all x

D

2 or 1 for all x.

Answer

2 or 1 according as x is rational or irrational

Explanation

Solution

1 + (cos2 n! πx)m

Case I

when x is irrational = 1 + (cos2 ∞)

= 1 + (0 to 1) = 1 + 0 = 1

put x = 0 when x is rational 1 + cos 0 = 2