Solveeit Logo

Question

Question: If \(x\) is measured in degree, then \(\dfrac{d}{{dx}}(\cos x)\) is equal to: A: \( - \sin x\) B...

If xx is measured in degree, then ddx(cosx)\dfrac{d}{{dx}}(\cos x) is equal to:
A: sinx - \sin x
B: 180πsinx - \dfrac{{180}}{\pi }\sin x
C: π180sinx - \dfrac{\pi }{{180}}\sin x
D: sinx\sin x

Explanation

Solution

Usually whenever it comes to trigonometric functions the xx will be measured in terms of radians. So to convert radians to degrees we have a formula, which is given by: xdegree=π180xradiansx\deg ree = \dfrac{\pi }{{180}}xradians. Now in place of xx substitute the value in terms of degree and solve for the correct answer.

Complete Step by Step Solution:
In the question they have given that xx is measured in terms of degree.
They have asked to find the derivative of cosx\cos x in terms of degree.
Usually in trigonometric functions, the value of xx will be given in terms of radians.
Here they are asking in terms of degree, so to convert radians to degree we have a relation between degree and radians given by:
xdegree=π180x radiansx\deg ree = \dfrac{\pi }{{180}}\text{x radians}
By using the above relation we need to find the required answer.
Given function is ddx(cosx)\dfrac{d}{{dx}}(\cos x)
Now, replace xx with π180x\dfrac{\pi }{{180}}x in the above function, we get
ddx(cosx)=ddx(cosπ.x180)\dfrac{d}{{dx}}(\cos x) = \dfrac{d}{{dx}}\left( {\cos \dfrac{{\pi .x}}{{180}}} \right)
Now, we know that differentiation of cosx\cos x is sinx - \sin x.so the above equation becomes,
ddx(cosπ.x180)=sinxddx(π180x)\dfrac{d}{{dx}}\left( {\cos \dfrac{{\pi .x}}{{180}}} \right) = - \sin x\dfrac{d}{{dx}}\left( {\dfrac{\pi }{{180}}x} \right)

sinxddx(π180x)=π180sinx \Rightarrow - \sin x\dfrac{d}{{dx}}\left( {\dfrac{\pi }{{180}}x} \right) = - \dfrac{\pi }{{180}}\sin x

Therefore when xx is measured in terms of degree then the derivative of cosx\cos x will be π180sinx - \dfrac{\pi }{{180}}\sin x. Hence option C is the correct answer.

Note:
In this conversion type problem one thing we need to remember is the conversion formula. In case of trigonometric functions we need to remember the derivative of all the functions, because they may ask for other trigonometric functions instead of cosx\cos x. Both conversion formula and derivative of trigonometric functions are important, if any one of these goes wrong while solving the problem then it may lead to the incorrect solution.