Question

If x is a positive integer satisfying $64 ≤ x ≤ 121$ and $y = \frac{x^2 + 4\sqrt{x}(x + 16) + 256}{x + 8\sqrt{x} + 16}$ then which of the following is satisfied by y?

• A. $39 ≤ y ≤ 68$
• B. $38 < y < 94$
• C. $40 < y ≤ 68$
• D. $42 ≤ y ≤ 78$
• E. $52 ≤ y ≤ 88$

Answer 1

Answer: (B)

$38 < y < 94$

Answer 2

The correct answer is option (B): $38 < y < 94$