Solveeit Logo

Question

Mathematics Question on Probability

If XX is a poisson variate such that P(X=1)=P(X=2)P(X = 1) = P(X = 2), then P(X=4)P(X=4) is equal to

A

12e2\frac{1}{2e^{2}}

B

13e2\frac{1}{3e^{2}}

C

23e2\frac{2}{3e^{2}}

D

1e2\frac{1}{e^{2}}

Answer

23e2\frac{2}{3e^{2}}

Explanation

Solution

Given : P(X=1)=P(X=2)P (X = 1) = P (X = 2)
eλ1!=eλλ22!\frac{e^{-\lambda}}{1!}=\frac{e^{-\lambda}\lambda^{2}}{2!}
λ=2\Rightarrow \lambda=2
P(x=4)=e2244!=23e2\therefore P\left(x=4\right)=\frac{e^{-2}2^{4}}{4!}=\frac{2}{3e^{2}}