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Question: If x is a continuous random variable then \[P(x \geqslant a) = \] A.\(P(x < a)\) B.\(1 - P(x > a...

If x is a continuous random variable then P(xa)=P(x \geqslant a) =
A.P(x<a)P(x < a)
B.1P(x>a)1 - P(x > a)
C.P(x>a)P(x > a)
D.1P(xa1)1 - P(x \leqslant a - 1)

Explanation

Solution

If we are given with continuous random variables such as X, we can only calculate the probability that X lies within a certain interval; like P(Xk)P(X \leqslant k)or P(aXb)P(a \leqslant X \leqslant b)
If the probability of X to be equal to a specific value then we can’t calculate the probability i.e.
P(X=k)=0\Rightarrow P(X = k) = 0
This fact remains true. As, the total number of possible values for a continuous random variable X is infinite so the possibility of any one single outcome tends towards 0.

Complete step-by-step answer:
A random variable where the data can have infinite values then it is called continuous random variable. For example, the time taken for something to be done is measured by a random variable and is continuous since there are an infinite number of possible times that can be taken.
Here in this question we have given that x is continuous random variable. Now we have given that x is a continuous random variable and we have to find the value of P(xa)P(x \geqslant a).
let us consider that there are n number of points in total since x is continuous, therefore
the total number of possible values is infinite i.e. nn \to \infty and hence the possibility of any single outcome i.e. a tends towards zero.
P(x=a)=1n\Rightarrow P(x = a) = \dfrac{1}{n}
As, nn \to \infty , therefore 1n0\dfrac{1}{n} \to 0. Hence,

P(x=a)=0 \Rightarrow P(x = a) = 0 ………..(1)

Now, we have to find the value of P(xa)P(x \geqslant a)as below:

P(xa)=P(x>a)+P(x=a) \Rightarrow P(x \geqslant a) = P(x > a) + P(x = a)
Put the value of equation 1 in this we get,
P(xa)=P(x>a)+0\Rightarrow P(x \geqslant a) = P(x > a) + 0
P(xa)=P(x>a)\Rightarrow P(x \geqslant a) = P(x > a)
Therefore, option C is the correct option.

Note: In this question students can make the mistake of taking the possibility of a single outcome as 1 and your answer will get wrong. As probability is the favourable outcome out of the total number of outcomes so here the outcome is 1 out of n points i.e. getting a when 1 is divided by infinity, we get 0.
If we want to calculate probability of continuous random variables i.e. probability the X lies between a certain range then we need two functions:
1.The probability density function (PDF)
2.The cumulative density function (CDF)