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Question

Mathematics Question on Probability

If XX is a binomial variate with the range 0,1,2,3,4,5,6\\{0,1,2,3,4,5,6\\} and P(X=2)=4P(X=4) P(X=2)=4 P(X=4) then the parameter pp of XX is

A

13\frac{1}{3}

B

12\frac{1}{2}

C

23\frac{2}{3}

D

34\frac{3}{4}

Answer

13\frac{1}{3}

Explanation

Solution

Here, n=6n=6
According to the question
6C2p2q4=4.6C4p4q2{ }^{6} C_{2} \,p^{2} \,q^{4}=4 .^{6}\, C_{4} \,p^{4} \,q^{2}
q24p2\Rightarrow q^{2}-4 p^{2}
(1p)2=4p2\Rightarrow(1-p)^{2}=4 p^{2}
3p2+2p1=0\Rightarrow 3 p^{2}+2 p-1=0
(p+1)(3p1)=0\Rightarrow(p+1)(3 p-1)=0
p=13\Rightarrow p=\frac{1}{3}
(p(\because p cannot be negative)