Question

If x gm is the mass of NaHC₂O₄ required to neutralise 100 ml of 0.2 (M) NaOH and y gm that required to reduce 100 ml of 0.02 (M) KMnO₄ in acidic medium, then

• A. x = y
• B. 2x = y
• C. x = 4y
• D. 4x = y

Answer 1

Answer: (C)

x = 4y

Answer 2

Let mol wt. of NaHC₂O₄ = M

\ $\frac{x}{M}$ = 100 × 0.2 × 10^–3 = 20 × 10^–3 ------(I)

$\frac{2}{5}$×$\frac{y}{M}$ = 100 × 0.02 ×10^–3 = 2 × 10^–3 ------II)

Dividing equation (I) by equation (II)

$\frac{5}{2}$× $\frac{x}{y}$ = 10

or x = 4y