If (x = \frac{1}{t^2}) and (y =\frac{1}{t^3}), then (\frac{d... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

If $x = \frac{1}{t^2}$ and $y =\frac{1}{t^3}$ , then $\frac{d^2y}{dx^2}$ at $t=1$ is:

A

$\frac{3}{2}$

B

$\frac{1}{2}$

C

$\frac{2}{3}$

D

$\frac{3}{4}$

Answer

$\frac{3}{4}$

Explanation

Solution

The correct option is(D): $\frac{3}{4}$