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Question: If X = e<sub>0</sub>L \(\frac{\Delta V}{\Delta t}\) here, e<sub>0</sub> = electrical permittivity o...

If X = e0L ΔVΔt\frac{\Delta V}{\Delta t} here,

e0 = electrical permittivity of free space

L = length

DV = potential difference Dt = time interval

then the dimensions of X is –

A

[M0L0T0A0]\lbrack M^{0}L^{0}T^{0}A^{0}\rbrack

B

[M0L0T0A2]\lbrack M^{0}L^{0}T^{0}A^{2}\rbrack

C

[M0L0T0A]\lbrack M^{0}L^{0}T^{0}A\rbrack

D

None of these

Answer

[M0L0T0A]\lbrack M^{0}L^{0}T^{0}A\rbrack

Explanation

Solution

[M1L3T4A2]×[L]×[M1L2T3A1][T]\frac{\lbrack M^{- 1}L^{- 3}T^{4}A^{2}\rbrack \times \lbrack L\rbrack \times \lbrack M^{1}L^{2}T^{- 3}A^{- 1}\rbrack}{\lbrack T\rbrack}= [ A ]