If (x = e^{y+e^y+.... to \space ∞}, x> 0) then (\frac{d^2y}{... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

If $x = e^{y+e^y+.... to \space ∞}, x> 0$ then $\frac{d^2y}{dx^2}$ is:

A

$-x^2$

B

$-\frac{1}{x^2}$

C

$\frac{1}{x^2}$

D

$x^2$

Answer

$-\frac{1}{x^2}$

Explanation

Solution

The correct option is(B): $-\frac{1}{x^2}$