Question
Question: If (x-c) is a factor of order m of the polynomial f(x) of degree n(1 < m < n), then x=c is the root ...
If (x-c) is a factor of order m of the polynomial f(x) of degree n(1 < m < n), then x=c is the root of the polynomial(where fr(x) represents rth derivative of f(x) w.r.t. x).
(a) fm(x)
(b) fm−1(x)
(c) fn(x)
(d) none of these
Solution
First, before proceeding for this, we must suppose a polynomial g(x) with degree (n-m) that is multiplied with the factor (x-c) with degree m to get the another polynomial which is defined in the question as f(x) as f(x)=(x−c)mg(x) . Then, x=c is a common root for all equations that comes from the derivative of the above function. Then, if we differentiate the above expression to the last degree to get (x=c) as a root, we get the last differentiation as fm−1(x)=0 which gives the final result.
Complete step-by-step answer:
In this question, we are supposed to find if x=c is the root of the polynomial when (x-c) is a factor of order m of the polynomial f(x) of degree n(1So, before proceeding for this, we must suppose a polynomial g(x) with degree (n-m) that is multiplied with the factor (x-c) with degree m to get the other polynomial which is defined in the question as f(x).
f(x)=(x−c)mg(x)
Then, x=c is a common root for all equation that comes from the derivative of the above function as:
f(x)=0,f′(x)=0,f′′(x)=0.... so on till the last term before the degree gets totally eliminated as fm−1(x)=0 .
So, fr(x) represents the rth derivative of the polynomial function f(x).
Moreover, if we differentiate the above expression to the last degree to get (x=c) as a root, we get the last differentiation as fm−1(x)=0 .
So, the (x=c) is the root of the polynomial fm−1(x) .
So, the correct answer is “Option b”.
Note: Now, to solve these type of the questions we need to know some of the basics of the differentiation as let us suppose the polynomial as f(x)=xn . Then, if we need to eliminate the entire power of the polynomial with power n, we need to perform the differentiation (n-1) times. So, the factor (x=c ) only occurs when fn−1(x)=0 is calculated.