Question

If x be real, then the minimum value of $x^{2} - 8x + 17$ is

• A. – 1
• B. 0
• C. 1
• D. 2

Answer 1

Answer: (C)

1

Answer 2

Since $a = 1 > 0$ therefore its minimum value is

$= \frac{4ac - b^{2}}{4a} = \frac{4(1)(17) - 64}{4} = \frac{4}{4} = 1$