Question

If $x =at + bt^2$ where $x$ is measured in m and t ins, thenthe dimension of (b/a) is

• A. $LT^2$
• B. $LT^{-1}$
• C. $T$
• D. $T^{-1}$

Answer 1

Answer: (D)

$T^{-1}$

Answer 2

Here, $x = at + bt^2$
Dimensionally, $x = at = bt^2$
or $\frac{b}{a} = \frac{t}{t^2} = \frac{1}{t}$
Dimension of $\left( \frac{b}{a}\right) = [T^{-1}]$