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Question: If x and y are complex numbers then system of equations \(\left( {1 + i} \right)x + \left( {1 - i} \...

If x and y are complex numbers then system of equations (1+i)x+(1i)y=1,2xi+2y=1+i\left( {1 + i} \right)x + \left( {1 - i} \right)y = 1,\,\,2xi + 2y = 1 + i has
(A) unique solution
(B) no solution
(C) infinite number of solution
(D) none of these

Explanation

Solution

Writing the given complex equation in standard form then solving equations obtained on comparing to get a number of solutions.
Formulas used: x+iy=a+ibx + iy = a + ib comparing real part with real part and imaginary part with imaginary part

Complete step by step solution.
Given, equations are (1+i)x+(1i)y=1\left( {1 + i} \right)x + \left( {1 - i} \right)y = 1 and2xi+2y=1+i2xi + 2y = 1 + i. Writing equation in standard form a+iba + ib
(1+i)x+(1i)y=1\left( {1 + i} \right)x + \left( {1 - i} \right)y = 1
x+ix+yiy=1\Rightarrow x + ix + y - iy = 1
(x+y)+i(xy)=1\Rightarrow \left( {x + y} \right) + i\left( {x - y} \right) = 1 Or
(x+y)+i(xy)=1+(0)i\Rightarrow \left( {x + y} \right) + i\left( {x - y} \right) = 1 + (0)i
x+y=1andxy=0x + y = 1\,\,and\,\,x - y = 0

Now, solving two equations x+y=1andxy=0x + y = 1\,\,and\,\,x - y = 0 obtained in step 1.
On adding two equations we have
2x=1 x=12  2x = 1 \\\ \Rightarrow x = \dfrac{1}{2} \\\
Substituting value of x=12x = \dfrac{1}{2} in either of the above equation to get the value of y.
12+y=1\Rightarrow \dfrac{1}{2} + y = 1
y=112\Rightarrow y = 1 - \dfrac{1}{2}
y=12\Rightarrow y = \dfrac{1}{2}
Therefore, the solution of the first complex equation is(12,12)\left( {\dfrac{1}{2},\dfrac{1}{2}} \right).

Now, writing second complex equation in standard form a+iba + ib
2xi+2y=1+i2xi + 2y = 1 + iOr
(2y)+2xi=1+i(2y) + 2xi = 1 + i
On comparing real and imaginary part on both sides.
2y=1and2x=12y = 1\,\,\,and\,\,2x = 1
y=12andx=12\Rightarrow y = \dfrac{1}{2}\,\,and\,\,x = \dfrac{1}{2}
Therefore, solution of second complex equation is(12,12)\left( {\dfrac{1}{2},\dfrac{1}{2}} \right)
Therefore, from above calculations we see that in step 3 and in step 4 solution obtained of the given complex equation is(12,12)\left( {\dfrac{1}{2},\dfrac{1}{2}} \right).

Hence, we say that solutions of the given complex equations is one or we can say equations have unique solutions.

Note: In complex problems solution of equations can be obtained by converting equations into standard form.