Question
Question: If \[x=a\cos \theta \] and \[y=b\sin \theta \], then \[{{b}^{2}}{{x}^{2}}+{{a}^{2}}{{y}^{2}}\] is eq...
If x=acosθ and y=bsinθ, then b2x2+a2y2 is equal to
A) ab
B) a2b2
C) a4b4
D) None of these
Solution
In the given question, we have been asked to find the value of the given trigonometric expression. In order to find the value of a given expression, first we need to simplify the given expression so that we can apply the trigonometric identity. After rewritten apply the trigonometric identity that is cos2θ+sin2θ=1. Later substituting the values, solve the given expression and then find the value of a function by using the calculator. In this way we will get the required answer.
Complete step-by-step solution:
We have given that,
x=acosθ and y=bsinθ
Now,
⇒x=acosθ
Therefore,
⇒cosθ=ax
Then,
We have,
⇒y=bsinθ
Therefore,
⇒sinθ=by
Using the trigonometric identity i.e.
⇒cos2θ+sin2θ=1
Therefore,
Substituting the values, we obtained
⇒a2x2+b2y2=1
Solving the above expression, by taking the LCM, we get
⇒a2b2x2b2+y2a2=1
Multiplying both the sides of the equation by a2b2, we get
⇒x2b2+y2a2=a2b2
Therefore, the value of b2x2+a2y2is equal to a2b2. It is the required answer.
Hence the option (B) is the correct answer.
Note: In order to solve these types of questions, you should always need to remember the properties of trigonometric and the trigonometric ratios as well. It will make questions easier to solve. It is preferred that while solving these types of questions we should carefully examine the pattern of the given function and then you would apply the formulas according to the pattern observed. As if you directly apply the formula it will create confusion ahead and we will get the wrong answer.