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Question: If x = 9 is the chord of contact of the hyperbola x<sup>2</sup> – y<sup>2</sup> = 9, then the equati...

If x = 9 is the chord of contact of the hyperbola x2 – y2 = 9, then the equation of the corresponding pair of tangents is –

A

9x2 – 8y2 + 18x – 9 = 0

B

9x2 – 8y2 – 18x + 9 = 0

C

9x2 – 8y2 – 18x – 9 = 0

D

9x2 – 8y2 + 18x + 9 = 0

Answer

9x2 – 8y2 – 18x + 9 = 0

Explanation

Solution

If x = 9 meets the hyperbola x2 – y2 = 9 at (9, 62\sqrt{2}) and (9, –62\sqrt{2}). The equations of the tangents to the hyperbola at these points are

3x – 22\sqrt{2}y – 3 = 0 and 3x + 22\sqrt{2}y – 3 = 0

Joint equation of the two tangents is therefore

(3x – 22\sqrt{2}y – 3) (3x + 22\sqrt{2}y – 3) = 0

Ž (3x – 3)2 – (22\sqrt{2}y)2 = 0 Ž 9x2 – 8y2 – 18x + 9 = 0.