Question

If $x=5\sin(\pi i+\frac{\pi}{3})m$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are :

• A. 5 cm, 2 s
• B. 5 m, 2 s
• C. 5 cm, 1 s
• D. 5 m ,1 s

Answer 1

Answer: (B)

5 m, 2 s

Answer 2

The amplitude is the coefficient of $\sin$: 5 m.
The angular frequency $\omega = \pi$,
and time period $T= \frac{2\pi}{\omega} = \frac{2\pi}{\pi} = 2 \, s$.