If x+√3y = 3 is the tangent to the ellipse 2x2 + 3y2 = k at... | Mathematics | SolveeIt | Solveeit

Today, August 19

Question

If x+√3y = 3 is the tangent to the ellipse 2x2 + 3y2 = k at a point P then the equation of the normal to this ellipse at P is

A

5x - 2√3y = 1

B

x - √3y = 2

C

x - √3y + 1 = 0

D

3x - √3y = 1

Answer

3x - √3y = 1

Explanation

Solution

The correct option is (D) 3x - √3y = 1