Question
Mathematics Question on Circle
If x,32,z are in AP;x,3,z are in GP; then which one of the following will be in HP?
A
(A) x,6,z
B
(B) x,4,z
C
(C) x,2,z
D
(D) x,1,z
Answer
(A) x,6,z
Explanation
Solution
Explanation:
Given: x,32,z are in AP∴2×32=x+z⇒x+z=3….1Now, x,3,z are in GP∴32=xz⇒xz=9….2Let x,y,z are in HP∴y=2xzx+z=2×93=6So, x,6,z are in HP.Hence, the correct option is (A).