Question: If x = 1998!, then value of the expression $\frac{1}{\log_{2}x}$+ $\frac{1}{\log_{3}x}$+……+ \(\f...

Question

If x = 1998!, then value of the expression $\frac{1}{\log_{2}x}$ + $\frac{1}{\log_{3}x}$ +……+ $\frac{1}{\log_{1998}x}$ equals-

Answer 1

Sum = log_x2 + log_x3 + log_x4 +…..+ log_x1998

= log_x 2.3.4…..1998 = log_xx = 1

Hence correct choice is

Question: If x = 1998!, then value of the expression \(\frac{1}{\log_{2}x}\)+ \(\frac{1}{\log_{3}x}\)+……+ \(\f...