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Question

Mathematics Question on Sequence and series

If x>1,y>1,z>1x > 1, y > 1, z > 1 are in GP, then 11+Inx,11+Iny,11+Inz,\frac{1}{1+In\, x}, \frac{1}{1+In\, y},\frac{1}{1+In\, z}, are in

A

AP

B

HP

C

GP

D

none of these

Answer

GP

Explanation

Solution

Let the common ratio of the GP be r. then
\hspace20mm y = xr and z=xr2z = xr^2
Iny=Inx+Inr\Rightarrow In\, y = \, In\, x + \, In\, r\, andInz=Inx+2Inr\, In\, z = \, In \, x + 2\, In \, r
Let \hspace10mm A =1 + In\, x, D = In\, r
Then, 11+Inx=1A,11+Iny=11+Inx+Inr=1A+D\frac{1}{1+In\, x} =\frac{1}{A}, \frac{1}{1+In\, y}=\frac{1}{1+In\, x +\, In\, r}= \frac{1}{A+D}
and 11+Inz=11+Inx+2Inr=1A+2D \, \, \, \frac{1}{1+In\, z} =\frac{1}{1+In\, x +2 \, In\, r}= \frac{1}{A+2D}
Therefore, 11+Inx,11+Iny,11+Inz\frac{1}{1+In\, x},\frac{1}{1+In\, y }, \frac{1}{1+In\, z} are in HP.