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Question

Mathematics Question on Binomial theorem

If x<1,|x|<1, then the coefficient of x6{{x}^{6}} in the expansion of (1+x+x2)3{{(1+x+{{x}^{2}})}^{-3}} is

A

3

B

6

C

9

D

12

Answer

3

Explanation

Solution

(1+x+x2)3=[1(1+x+x2)]3{{(1+x+{{x}^{2}})}^{-3}}={{\left[ \frac{1}{(1+x+{{x}^{2}})} \right]}^{3}}
=[1x1x3]3={{\left[ \frac{1-x}{1-{{x}^{3}}} \right]}^{3}}
=(1x)3(1x3)3={{(1-x)}^{3}}{{(1-{{x}^{3}})}^{-3}}
=(1x33x2+3x)(1+3x3+6x6+.....)=(1-{{x}^{3}}-3{{x}^{2}}+3x)(1+3{{x}^{3}}+6{{x}^{6}}+.....)
\therefore Coefficient of x6{{x}^{6}} in (1+x+x2)3{{(1+x+{{x}^{2}})}^{-3}}
=63=3=6-3=3