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Question: If x∈ \[–1, 0) then cos<sup>–1</sup>(2x<sup>2</sup> –1) –2 sin<sup>–1</sup>x equals...

If x∈ [–1, 0) then cos–1(2x2 –1) –2 sin–1x equals

A

−π2\frac { - \pi } { 2 }

B

3π2\frac { 3 \pi } { 2 }

C

–2p

D

None

Answer

None

Explanation

Solution

\ cos–1(2x2–1) = 2p – 2cos–1x if x < 0

So, 2p – 2cos–1x – 2sin–1x = p