Question

If $(x - a)(x - b) + (x - b)(x - c) + (x - c)(x - a) = 0$are the roots of the equation $2x^{2} + 3(\lambda - 2)x + \lambda + 4 = 0$then the value of $\lambda$is equal to.

• A. $(p^{2} + q^{2})x^{2}$
• B. $- 2q(p + r)x$
• C. $(q^{2} + r^{2}) = 0$
• D. $p,q,r$

Answer 1

Answer: (C)

$(q^{2} + r^{2}) = 0$

Answer 2

Sum of root $= 2\log(x + 1)$ and product of roots $x^{2} - |x + 2| + x > 0,$

So, $( - \infty, - 1) \cup (1,\infty)$

= $(\sqrt{2},\infty)$