Question

If work W is done in blowing a bubble of radius R from a soap solution, then the work done in blowing a bubble of radius 2R from the same solution is

• A. W/2
• B. 2W
• C. 4W
• D. $2 \frac { 1 } { 3 }$W

Answer 1

Answer: (C)

4W

Answer 2

$W = 8 \pi R ^ { 2 } T$∴$W \propto R ^ { 2 }$ (T is constant)

If radius becomes double then work done will become four times.