Question
Question: If we have an expression \[x + y + z = 0,\left| x \right| = \left| y \right| = \left| z \right| = 2\...
If we have an expression x+y+z=0,∣x∣=∣y∣=∣z∣=2 and θ is angle between y and z then the value of 2cosec2θ+3cot2θ is:
1. 311
2. 38
3. 35
4. 1
Solution
Here in this question we will use the concepts of vectors like mod of vector and dot product of two vectors to find the required solution. Also we have to use the basic trigonometric values in terms of their relation with the sides of a right angled triangle.
A vector is a quantity that has both magnitude, as well as direction. Some mathematical operations can be performed on vectors such as addition and multiplication.
Complete step-by-step solution:
We are given x+y+z=0,∣x∣=∣y∣=∣z∣=2 and θ is the angle between y and z .
We are to find the value of 2cosec2θ+3cot2θ .
Therefore we get y+z=−x
Taking mod on both the sides we get ,
∣y+z∣=∣x∣
Squaring both sides we get ,
∣y+z∣2=∣x∣2
∣y∣2+∣z∣2+2∣y∣∣z∣cosθ=∣x∣2
Since we are given ∣x∣=∣y∣=∣z∣=2
Putting these values in the above equation we get ,
4+4+2(2)(2)cosθ=4
On simplifying the expression we get ,
cosθ=−21
Squaring both sides we get ,
cos2θ=41
Using the identity sin2θ+cos2θ=1.
Hence we get sin2θ=43
Therefore consider 2cosec2θ+3cot2θ
This can be rewritten as sin2θ2+3cos2θ
Putting the values of cos2θ and sin2θ we get ,
sin2θ2+3cos2θ=(43)2+3(41)=311
Hence we get the value for the required expression.
Therefore option (1) is the correct answer.
Note: To solve such types of questions one needs to have knowledge of vectors and their properties like dot product, cross product etc. Also one must be aware of all the concepts of trigonometry , its related formulas and basic trigonometric identities. In addition to these we must know their relation with the sides of a right angled triangle. We must do the calculations carefully and should recheck at each and every step in order to get the exact solution.