Question
Question: If we have an equation \(y=\sqrt{x}+\dfrac{1}{\sqrt{x}}\) , then \(\dfrac{dy}{dx}\) at \(x=1\) is ...
If we have an equation y=x+x1 , then dxdy at x=1 is
A)!
B). 21
C). 21
D). 0
Explanation
Solution
In the given question, we need to find the derivative of the given function that involves square root within it. We know that derivatives are the rate of change of one variable with respect to another variable. It is also the slope of the tangent.
Complete step-by-step solution:
According to the given question, we need to find the derivative of the function y=x+x1. Derivatives are basically known as the rate of change of one variable with respect to another variable.
Now, we know that derivative of xn=nxn−1 . So, using this in the given question we will get the derivative of the function which is denoted by y′(x) .
Therefore,