Question
Question: If we have a determinant as \[Z=\left| \begin{matrix} 1 & 1+2i & -5i \\\ 1-2i & -3 & 5+3i ...
If we have a determinant as Z=1 1−2i 5i 1+2i−35−3i−5i5+3i7 then (i=−−1)
A) z is purely real
B) zis purely imaginary
C) z+z=0
D) z−z=0 is purely imaginary
Solution
i stands for iota. It is also called the imaginary part. A complex number has the real part and the imaginary part. The complex numbers are the field of numbers of the form x+iy , where and y are real numbers and i is the imaginary unit equal to the square root of −1,−1 . When a single letter z=x+iy is used to denote a complex number, it is also called an "affix." In component notation, z=x+iy can be written(x,y). The field of complex numbers includes the field of real numbers as a subfield. An m×n complex matrix is a rectangular array of complex numbers arranged in m rows and n columns. Addition and scalar multiplication of complex matrices can be performed. We can represent the complex number z=x+iy as the matrix x y −yx . The reciprocal of a complex number is given as the inverse of its matrix representation; we can see that complex division can be given as multiplying the matrix representation of the numerator by the inverse matrix of the denominator. If x=0, then z=0+iy is purely imaginary. If y=0, then z=x+0i is purely real.
Complete step-by-step solution:
According to the question,