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Question: If wavelength of photon is\(X^{3 -}h = 6.6 \times 10^{- 34}\)*J-sec,* then momentum of photon is...

If wavelength of photon isX3−h=6.6×10−34X^{3 -}h = 6.6 \times 10^{- 34}J-sec, then momentum of photon is

A

3×10−23kgms−13 \times 10^{- 23}kgms^{- 1}

B

3.33×1022kgms−13.33 \times 10^{22}kgms^{- 1}

C

1.452×10−44kgms−11.452 \times 10^{- 44}kgms^{- 1}

D

6.89×1043kgms−16.89 \times 10^{43}kgms^{- 1}

Answer

3×10−23kgms−13 \times 10^{- 23}kgms^{- 1}

Explanation

Solution

p=hλ=6.6×10−342.2×10−11=3×10−23kgms−1p = \frac{h}{\lambda} = \frac{6.6 \times 10^{- 34}}{2.2 \times 10^{- 11}} = 3 \times 10^{- 23}kgms^{- 1}