If W is weight of the chain, L is span and P is tension or p... | Physics | SolveeIt | Solveeit

Today, August 24

Question

If W is weight of the chain, L is span and P is tension or pull, then sag correction for chain line will be.

A

$\frac{W^2L^2}{24P6^2}$

B

$\frac{W^2L}{24P}$

C

$\frac{W^2L}{24P^2}$

D

$\frac{W^2L^2}{24P}$

Answer

$\frac{W^2L}{24P}$

Explanation

Solution

The correct option is(B): $\frac{W^2L}{24P}$