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Question

Physics Question on mechanical properties of fluid

If W1W_{1} be the work to be done to form a bubble of volume VV from a given solution. The work required to be done to form a bubble of volume 2V2 V is

A

42/3W14^{2/3} \, W_{1}

B

41/3W14^{1/3} \, W_{1}

C

21/2W12^{1/2} \, W_{1}

D

23/2W12^{3/2} \, W_{1}

Answer

41/3W14^{1/3} \, W_{1}

Explanation

Solution

Here, volume of bubble, V=43πR3V=\frac{4}{3}\pi R^{3} or R=(3V4π)1/3R=\left(\frac{3V}{4\pi}\right)^{1 /3} Work done, W=S×8πR2=S×8π(3V4π)2/3W=S\times8\pi R^{2}=S\times8\pi\left(\frac{3V}{4\pi}\right)^{2 /3} or WV2/3W \propto V^{2/ 3} W2W1=(V2V1)2/3\therefore \frac{W_{2}}{W_{1}}=\left(\frac{V_{2}}{V_{1}}\right)^{2/ 3} =(2VV)2/3=22/3=\left(\frac{2V}{V}\right)^{2 /3}=2^{2/ 3} W2=41/3W1\therefore W_{2}=4^{1 /3} W_{1}