Question

If volume of $2$ moles of an ideal gas at $540 \,K$ is $44.8$ litre, then its pressure will be

• A. $1 \,atm$
• B. $3 \,atm$
• C. $2 \,atm$
• D. $4 \,atm$

Answer 1

Answer: (C)

$2 \,atm$

Answer 2

Number of moles, $n = 2$ Temperature, $T = 540\, K$ Volume, $V = 44.8\, L$ $P=?$ [$R$, gas constant $= 0.0821\, L \,atm \,K^{-1}\, mol^{-1}$] According to ideal gas equation $PV = nRT$ $P=\frac{nRT}{V}=\frac{2\times0.0821\times540}{44.8}$ $=2\,atm$